2 162 154 180 164 166 157 171 175 Determine the mean, standard deviation, and five-number summary for the data. a. Mean is 160.12; Standard deviation is 19.8. Five-number summary: min = 120, 4072-02-01-06-00_files/i0290000.jpg= 148, median = 162, 4072-02-01-06-00_files/i0290001.jpg= 174, max = 202 b. Mean is 162; Standard deviation is 19.8. Five-number summary: min = 120, 4072-02-01-06-00_files/i0290002.jpg= 148, median = 160.12, 4072-02-01-06-00_files/i0290003.jpg= 174, max = 202 c. Mean is 160.12; Standard deviation is 15.5. Five-number summary: min = 202, 4072-02-01-06-00_files/i0290004.jpg= 148, median = 160.12, 4072-02-01-06-00_files/i0290005.jpg= 174, max = 120 d. Mean is 162; Standard deviation is 15.5. Five-number summary: min = 202, 4072-02-01-06-00_files/i0290006.jpg= 148, median = 162, 4072-02-01-06-00_files/i0290007.jpg= 174, max = 120