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3 years ago

Explain 657 divide by 3 using partial quotient

Mathematics

1 answer:

RideAnS [48]3 years ago

8 0

657/3=219 is the easy way out but thats not what is being asked here so 100*6+57/3=219

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Which of the following graphs has a zero at (-5)?

guapka [62]

Graph B would be the correct answer

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2 years ago

Which equation can be used to determine p, the cost of s swimsuits

ch4aika [34]

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6 0

3 years ago

X^2-8x+16 divided by ax-4x numerator

Vedmedyk [2.9K]

Answer:

Given:

1). $x^2-8x+16$ divided by $x-4$

⇒ $\frac{x^2-8x+16}{x-4}$

⇒ $\frac{x^2-2\times x\times 4+4^2}{x-4}$

By factorising numerator by using identity, $(a-b)^2=a^2-2\times a \times b +b^2$

⇒ $\frac{(x-4)^2}{x-4}$

⇒ $\frac{(x-4)\times(x-4)}{x-4}$

⇒ $x-4$ {Answer}

2). $3x^2y$ divided by $6xy^2$

⇒ $\frac{3x^2y}{6xy^2}$

⇒ $\frac{3\times x\times x\times y}{6\times x\times y\times y}$

⇒ $\frac{x}{2y}$ { Answer}

4 0

4 years ago

Hund’s rule of maximum multiplicity specifies that _____. A. electrons will fill orbitals of lower energy first, pairing up only

djverab [1.8K]

Answer:

A. electrons will fill orbitals of lower energy first, paring up only after each orbital of the same energy already has one electron

Step-by-step explanation:

The rule states that for a given electron configuration, the lowest energy term is the one with the greatest value of spin multiplicity. This implies that if two or more orbitals of equal energy are available, electrons will occupy them singly before filling them in pairs.

4 0

3 years ago

ε = {x: 2 x 30, x is an integer}, M = {even numbers}, P = {prime numbers}, T = {odd numbers} Find: I) MUP ii) M - T iii) P(MT) i

mariarad [96]

Answer:

Step-by-step explanation:

ε = {x: 2≤ x ≤30}

M = { even numbers} = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}

P = { prime numbers} = {2,3,5,7,11,13,17,19,23,29}

T = {odd numbers} = {3, 5, 7, 9, 11,13,15,17,19,21,23,25,27,29}

1. M ∪ P = {2,3,4,5,6,7,8,10,11,12,13,14,16,17,18,19,20,22,23,24,26,28,29,30}

2. M - T =

n(M) - n(T)

15- 14 = 1

3. P(MT)

(MT) = M ∩ T = 0

P ∪ (M ∩ T ) = {2,3,5,7,11,13,17,19,23,29}

4. P' = not a prime number

T' = not odd number = M

P' ∪(M∩T')

P' ∪ {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}

= {2,4,6,8,9,10,12,14,15,16,18,20,21,22,24,25,26,27,28,30}

6 0

3 years ago