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3 years ago

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The Potter Valley basketball team did not record how many baskets each player made during the last game. Jenny remembers that sh

e made three times as many baskets as Grace. Alexis knows that she made six more baskets than Grace. Joan thinks that she made 4 fewer baskets than Grace. Tammy is sure that she made the same number of baskets as Joan. Altogether the five players made 40 baskets. How many baskets did each player make?

1 answer:

lesya692 [45]3 years ago

5 0

Answer: The approximate values that every player make are,

Tammy = grace = 5.43 baskets

Jenny = 16.30 Baskets

Alex = 11.43 Baskets

Joan = 1.43

Step-by-step explanation:

Let Grace made x baskets.

Then According to the question,

Jenny made baskets = 3x

Alexis made basket = x + 6

Joan made basket = x - 4

Tammy made baskets = x

Since, Altogether the five players made 40 baskets.

⇒ x+ 3x + x + 6 + x - 4 + x = 40

⇒ 7x + 2 = 40

⇒ 7x = 38

⇒ x = 38 / 7 = 5.42857142857 ≈ 5.43

Thus, Grace made baskets= Tammy made baskets = x = 5.43

Jenny made baskets = 3 × x = 16.2857142857 ≈ 16.30

Alexis made basket = x + 6 = 11.4285714286 ≈ 11.43

Joan made basket = x - 4 = 1.42857142857

≈ 1.43

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Step-by-step explanation:

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Answer:

(a) The probability that the student made the Dean's list is 0.1655.

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Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

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The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

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