All categories

4 years ago

One-third times the difference of a number and 5 is -2/3

Mathematics

1 answer:

fomenos4 years ago

3 0

The answer is 3. 1/3(x-5)= -2/3. Multiply by 3 on both sides. Add five and you get 3

You might be interested in

What is y+2= (-3) (x-4)

TEA [102]

Y=-3x+10 is your awnser

3 0

3 years ago

Read 2 more answers

Help help help help help math

almond37 [142]

Step-by-step explanation:

don't panic. just breathe and think logically.

why would these angles be different ? how could they be different ?

right : they cannot be different. otherwise the 2 horizontal lines would not be parallel.

so, yes, indeed, these 2 angles are identical.

3x + 2 = 2x + 6

x = 4

that's it.

7 0

2 years ago

A bowling ball weighs 48 N. With what net force must it be pushed to accelerate it at 3.0 m/s2

arsen [322]

First find the mass.
Since weight force is 48N, and acceleration due to gravity is 9.8 m/s^2,
weight force = mass*acceleration due to gravity,
mass = weight/acceleration
mass = 48N / 9.8 m/s^2
mass = 4.9 kg

Now you find the force needed to accelerate to 3.0 m/s^2.
Force = mass*acceleration
Force = 4.9kg * 3.0 m/s^2
Force = 14.7 N

8 0

4 years ago

Find the slant height of the cone with the given measurements, rounded to the nearest hundredth. Then use your result to find th

Alex73 [517]

Check the picture below.

$\bf \textit{surface area of a cone}\\\\ SA=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad \implies SA=\pi (8)\sqrt{164}+ \pi (8)^2 \\\\\\ SA=8\pi \sqrt{164}+ 64\pi \implies \stackrel{\pi =3.14~\hfill }{SA\approx 522.65296}\implies \stackrel{\textit{rounded up}}{SA=522.65}$

6 0

4 years ago

Read 2 more answers

from the edge of a 486-foot cliff, peyton shot an arrow over the ocean with an initial upward velocity of 90-feet per second

anygoal [31]

Answer:

9 seconds

Step-by-step explanation:

The complete question is

The altitude of an object, d, can be modeled using the equation below:

d=-16t^2 +vt+h

from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?

Let

d ----> the altitude of an object in feet

t ---> the time in seconds

v ---> initial velocity in ft per second

h ---> initial height of an object in feet

we have

$d=-16t^2 +vt+h$