Answer:
C) They are perpendicular lines.
Step-by-step explanation:
We first need to find the slope of the graph of the lines passing through these points using:

The slope of the line that passes through (−12, 15) and (4, −5) is


The slope of the line going through (−8, −9) and (16, 21) is



The product of the two slopes is

Since

the two lines are perpendicular.
To find this:
15/100*20 =
3/20*30 =
3
You can divide both numbers by 6 to get 2/15 (which cannot be simplified anymore)
2/15 is the simplified form
Answer:
Step-by-step explanation:
Since the angles both come off of the straight line, they are supplementary, and they add up to equal 180 degrees.
2x + 4x + 24 = 180 and
6x + 24 = 180 and
6x = 156 so
x = 26
Answer: 
Step-by-step explanation:
<h3>
The missing graph is attached.</h3><h3>
And the options are:</h3>

By definition, a relation is a function if and only if each input value has one and only one output value.
It is important to remember that the input values are the values of "x" and the output values are the values of "y".
Observe the graph attached.
You can identify in the graph that the function f(x) and the function g(x) intersect each other at the following point:

Where the x-coordinate (input value) is:

And the y-coordinate (output value) is:

Therefore, you can conclude that the input value that produces the same output value for the two functions on the graph, is:
