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iren2701 [21]
3 years ago
14

Mike decided to sell all of his old books he gathered up 9 books to sell he sold 2 books in a yard sale how many books does mike

now have
Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer: He has 7 books.

Step-by-step explanation:

9 - 2 = 7

ziro4ka [17]3 years ago
4 0

Answer:

7

Step-by-step explanation:

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Fittoniya [83]

Answer:

9x+18

Step-by-step explanation:

7 0
2 years ago
Which is greater 6 hundred thousands,47 tens or 60 ten thousands, 4 hundreds
Valentin [98]

Which is greater? Try writing out your amounts numerically sothe first one would write numerically, 600,000, the next is 047, the next is 60,000 & the last is 400 so your answer would be the first answer of 600,000.

4 0
3 years ago
What is 7/3 times 2/3 multiplied in simplest form
Sav [38]
Multiplying fractions is simple. You just multiply across so 7/3 x 2/3 is 14/9 and that is the simplest form.
4 0
2 years ago
Read 2 more answers
Explanations not just answers: Sarah measures the angle of elevation to the top of a tree as 23.6 degrees from the point which i
Reika [66]
See the attached diagram.

In the right triangle, x is opposite the 23.6 degree angle, and the adjacent side is 250 m.  This suggests using the tangent ratio.

\frac{x}{250}=\tan 23.6 ^\circ \\ x=250 \cdot \tan 23.6^\circ \approx 109.2

Finally, to get the height of the tree, add Sarah's height, 1.5 m.

The tree is approximately 110.7m tall.

6 0
3 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
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