Following transformations on Triangle ABC will result in the Triangle A'B'C'
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)
In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)
First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'.
Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'.
The same way C is translated to C'.
Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
The complement of the set is {8, 9, 10, 11}
<h3>How to find the complement of the set?</h3>
The universal set is given as:
U = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}.
The other set is given as:
{x | x is in N and x < 8}
The complement of the set is the set elements that are in the universal set, but not in the given set
The set {x | x is in N and x < 8} can be rewritten as
X = {0, 1, 2, 3, 4, 5, 6, 7}
So, the complement is
X' = {8, 9, 10, 11}
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Answer:
The slope is 1/2 in the positive direction
Step-by-step explanation:
Let us start with the basic slope equation:
rise/ run= slope
Now if we look at our graph, we can derive that the line is increased.
Then we look at two parts of the line which lie on a proper point of the graph.
In this case, I looked at (-4,0) and (-2,1).
The rise in this case is 1 while the run is 2.
Putting this into the equation gives us 1/2.
Answer:
your answer is c. yes
Step-by-step explanation:
hope it helps you