Answer:
The correct option is;
Simpson Paradox
Step-by-step explanation:
The phenomenon whereby particular trends are prevalent in small data portions but are not evident or an inverse trend is observe when the portions are joined together is known as Simpson's paradox.
Whereby the data for calculating the bating averages as found online are given as follows;
Season, Derek Jeter David Justice
1995, 12/48 = 0.250 104/411 ≈ 0.253
1996, 183/582 ≈ 0.314 45/140 ≈ 0.321
The overall hits to the overall bats ratio are;
, (183 + 12)/(582 + 48) ≈0.310 (104+45)/(411+140) = 0.27
Which shows that Derek Jeter's overall average was better than Justice's average
Answer:
the area after 6 years is 3,473 km^2
Step-by-step explanation:
The computation of the area after 6 years is as follows:
= Area × (1 - decreased percentage)^number of years
= 4,800 km^2 × (1 - 5.25%)^6
= 4,800 km^2 × 0.9475^6
= 3,473 km^2
Hence, the area after 6 years is 3,473 km^2
Answer:
the first time I saw the girls in the us was the day I think of it is the most
Step-by-step explanation:
I am a good man and a great man and a great wife but she doesn't have a good relationship but I am a good job and I am not the right one to be a good job and I had to do that for the first one and then we got you a new phone and I am sorry for bothering her to keep you from the situation I have a problem and you are not going talk about this and that you have to be careful about to leave your house in a bad way back then and you can do you better than you do that you don't have a relationship
Part A: f(t) = t² + 6t - 20
u = t² + 6t - 20
+ 20 + 20
u + 20 = t² + 6t
u + 20 + 9 = t² + 6t + 9
u + 29 = t² + 3t + 3t + 9
u + 29 = t(t) + t(3) + 3(t) + 3(3)
u + 29 = t(t + 3) + 3(t + 3)
u + 29 = (t + 3)(t + 3)
u + 29 = (t + 3)²
- 29 - 29
u = (t + 3)² - 29
Part B: The vertex is (-3, -29). The graph shows that it is a minimum because it shows that there is a positive sign before the x²-term, making the parabola open up and has a minimum vertex of (-3, -29).
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Part A: g(t) = 48.8t + 28 h(t) = -16t² + 90t + 50
| t | g(t) | | t | h(t) |
|-4|-167.2| | -4 | -566 |
|-3|-118.4| | -3 | -364 |
|-2| -69.6 | | -2 | -194 |
|-1| -20.8 | | -1 | -56 |
|0 | -28 | | 0 | 50 |
|1 | 76.8 | | 1 | 124 |
|2 | 125.6| | 2 | 166 |
|3 | 174.4| | 3 | 176 |
|4 | 223.2| | 4 | 154 |
The two seconds that the solution of g(t) and h(t) is located is between -1 and 4 seconds because it shows that they have two solutions, making it between -1 and 4 seconds.
Part B: The solution from Part A means that you have to find two solutions in order to know where the solutions of the two functions are located at.
