Question

Two equations are given below:

Answer 1

$\left \{ {{a - 3b = 16} \atop {a = b - 2}} \right. \\ \\ \left \{ {{a = 16 + 3b} \atop { 16 + 3b = b - 2}} \right. \\ \\ \left \{ {{a = 16 + 3b} \atop {3b - b = - 2 - 16}} \right. \\ \\ \left \{ {{a =16 + 3b} \atop {2b = -18}} \right. \\ \\ \left \{ {{a=16 + 3b} \atop {b=-9}} \right. \\ \\ \left \{ {{a=16 + 3b = 16 + 3*(-9) = 16 - 27 = -11} \atop {b=-9}} \right.$

Answer a = -11, b = -9