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3 years ago

13

in a quadrilateral, two of the angles each have a measure of 40°, and the measure of a third angle is 130°. What is the measure

of the remaining angle?

1 answer:

Tju [1.3M]3 years ago

8 0

The total sum of a quadrilateral is 360 degrees. 360-40-40-130=150 degrees.
Therefore the answer is 150 degrees.

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The graph represents the function g(x). Suppose that f(x) = -x. Which is true when comparing the range of f(x) to g(x)?

Inessa05 [86]

Answer:

The answer is A

Step-by-step explanation

7 0

3 years ago

How do we solve for x

blondinia [14]

X/2 + 5 = -10
x/2 = -10 - 5
x/2 = -15
x = -15(2)
x = -30

3 0

3 years ago

Amber mother gives her $15and she saves $3 a week. The expression 15+3w gives the amount she saves after w weeks. How much money

Mariulka [41]

After 2 weeks:
15+3(2)=15+6= $21
After 5 weeks:
15+3(5)=15+15= $30
After 10 weeks:
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Hope this helps

4 0

3 years ago

Read 2 more answers

Which is an example of an algebraic expression?

azamat

An algebraic expression doesnt have an equals sign or an inequality sign.

So,

A is an expression
B is an inequality
C is an equation
D is an in inequality

So the answer is A

5 0

4 years ago

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,

valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

$\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)$

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

$P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})$

$=P(Z>2.63)\\=1-P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0

3 years ago