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2 years ago

9

Help please! I'll mark brainliest!

1 answer:

Misha Larkins [42]2 years ago

3 0

23 need to use formula then calculate

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Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

GarryVolchara [31]

<u>Question 6</u>

1) $\overline{AB} \cong \overline{BD}$ , $\overline{CD} \perp \overline{BD}$ , O is the midpoint of $\overline{BD}$ , $\overline{AB} \cong \overline{CD}$ (given)

2) $\angle ABO, \angle ODC$ are right angles (perpendicular lines form right angles)

3) $\triangle ABO, \triangle CDO$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{BO} \cong \overline{OD}$ (a midpoint splits a segment into two congruent parts)

5) $\triangle ABO \cong \triangle CDO$ (LL)

<u>Question 7</u>

1) $\angle ADC, \angle BDC$ are right angles), $\overline{AD} \cong \overline{BD}$

2) $\overline{CD} \cong \overline{CD}$ (reflexive property)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\triangle ADC \cong \triangle BDC$ (LL)

5) $\overline{AC} \cong \overline{BC}$ (CPCTC)

<u>Question 8</u>

1) $\overline{CD} \perp \overline{AB}$ , point D bisects $\overline{AB}$ (given)

2) $\angle CDA, \angle CDB$ are right angles (perpendicular lines form right angles)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{AD} \cong \overline{DB}$ (definition of a bisector)

5) $\overline{CD} \cong \overline{CD}$ (reflexive property)

6) $\triangle ADC \cong \triangle BDC$ (LL)

7) $\angle ACD \cong \angle BCD$ (CPCTC)

8 0

1 year ago

Please hurry. Solve the equation

Lelu [443]

The value of x is $5\sqrt[3]{25}$ .

Solution:

Given expression is $-7=8-3 \sqrt[5]{x^{3}}$ .

Switch both sides.

$8-3 \sqrt[5]{x^{3}}=-7$

Subtract 8 from both side of the equation.

$8-3 \sqrt[5]{x^{3}}-8=-7-8$

$-3 \sqrt[5]{x^{3}}=-15$

Divide by –3 on both side of the equation.

$$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}$

$\sqrt[5]{x^{3}}=-5$

To cancel the cube root, raise the power 5 on both sides.

$(\sqrt[5]{x^{3}})^5=(-5)^5$

$x^3=3125$

To find the value of x, take square root on both sides.

$\sqrt[3]{x^3}=\sqrt[3]{25}$

$x=5\sqrt[3]{25}$

Hence the value of x is $5\sqrt[3]{25}$ .

5 0

3 years ago

A pipe is leaking at the rate of 8 fluid ounces per minute. How many gallons is the pipe leaking per hour

Phoenix [80]

Answer: 3.75 gallons

Step-by-step explanation:

8 fl oz x 60 (minutes)=480 fl oz

480 fl oz ÷ 128=3.75 gallons

7 0

3 years ago

Read 2 more answers

1). 3x-8 for x=5<br><br> 2). 5(x+7)-1 for x = -3

Serjik [45]

1. =7
2.=19
Please let me know if you got it correct!

4 0

3 years ago

30 red marbles is 40% of ____ marbles.

g100num [7]

Answer - 75

Sorry if it is wrong

7 0

3 years ago