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RoseWind [281]
2 years ago
8

Suppose your friend's parents invest $20000 in an account paying 7% compounded annually. What will the balance be in 7 years

Mathematics
2 answers:
Greeley [361]2 years ago
3 0
The balance will be: <span>$500,637.91



</span>
CaHeK987 [17]2 years ago
3 0
The formula for compound interest is:

I = P(1 +  \frac{r}{n} ) ^{nt}

Where P is the amount you start with, r is the rate, t is the time, and n is the number of times the interest is calculated per year. So for you, this would look like:

I = 20000(1 +  \frac{0.05}{1}) ^{1*7}

Hope it helps!
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Help me solve this pleaseeee
MaRussiya [10]

Answer:

f(n) = 6n + 12

Step-by-step explanation:

There is a common difference in consecutive number of seats, that is

42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 18 and d = 6 , then

f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12

5 0
3 years ago
Find the perimeter and area of the figure.
iogann1982 [59]

Answer:

perimeter of the figure =32 units

area of the figure=56 units²

8 0
3 years ago
Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

6 0
3 years ago
Use the distributive property to simplify the following expression: -3(-x - 3y)
alexandr402 [8]

Step-by-step explanation:

-3(-x -3y) = 3( x +3y) = 3x+9y

7 0
3 years ago
Help me answer the circled one please
SpyIntel [72]
48 and 6/8 that is the answer
3 0
3 years ago
Read 2 more answers
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