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2 years ago

1.) What is the domain and range of the function in the graph?

Mathematics

1 answer:

olga_2 [115]2 years ago

8 0

Answer:

Domain → (-∞, ∞)

Range → (-2, ∞)

Step-by-step explanation:

1). Domain of a function is defined by the input values (set of x-values) and Range of the function is defined by the output values (set of y-values).

From the graph attached,

Function is defined for all real values of x.

Therefore, domain of the function will be (-∞, ∞).

On y-axis values of the function vary from -2 (excluding 2) to positive infinity.

Therefore, range of the function will be (-2, ∞).

2). Average rate of change of a function in the interval (a, b) is defined by,

Average rate of change = $\frac{f(b)-f(a)}{b-a}$

By using this expression we can find the average rate of change in the given interval.

Please give the correct interval for which the average rate of change is to be calculated.

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3 years ago

Letters A and B represent a question]MATH

LiRa [457]

Answer:

@Genius102 has answered this already, but here it is

Step-by-step explanation:

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3 years ago

A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

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3 years ago

Convert 0.00049 to scientific notation.

SOVA2 [1]

It's 10 - 4

moving decimal over to the right makes a negative exponent.

7 0

3 years ago

Read 2 more answers

Use a number line to add:

Jobisdone [24]

Start at 14 on the number line. Since 25 is negative you’re going to be moving to the left. After 14 hops you’ll reach zero, you’re adding -25 so you’ll have to reach a total of 25 hops to the left. You have moved so far 14 hops so you still have 11 to go. Moving 11 more hops to the left results in -11. Now you have reached the total number of hops 25, the negative sign indicated you were moving towards the left. So 14+(-25)=-11

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2 years ago