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3 years ago

Solve the equation 5-(n--4)=3(n+2)

Mathematics

1 answer:

DedPeter [7]3 years ago

7 0

5-(n-4)=3(n+2)
5-n+4=3n+6
9-n=3n+6
3=4n
n=3/4

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Given:

The height of the given trapezoid = 6 in

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Also given, one base of the trapezoid is 6 inches longer than the other base

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Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

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$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

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