7 - 5n = 6 + 6(n + 2)

Plzzz help. Solve for x. Your answer must be simplified. 2x<15

tino4ka555 [31]

For all values of x less than 7.5 the above inequality satisfies , i.e $x$

Step-by-step explanation:

Inequalities are the relationships between two expressions which are not equal to one another. The symbols used for inequalities are <, >, ≤, ≥ and ≠.

$7 \textgreater x$ reads as '7 is greater than x' (or ' x is less than 7', reading from right to left).

$x \leq -4$ reads as ' x is less than or equal to -4' (or '-4 is greater than or equal to x', reading from right to left).

$x \neq 5$ reads as ‘ x is not equal to 5.

Here , we have

$\begin{aligned}&2 x$ { Dividing both sides by 2. }

∴ For all values of x less than 7.5 the above inequality satisfies.

5 0

3 years ago

Read 2 more answers

What is the value of y?

Amiraneli [1.4K]

Answer:

$\boxed{D. \: 40\degree}$

Step-by-step explanation:

Angle sum property of triangle states that the sum of interior angles of a triangle is 180°

So,

$= > 2y \degree + (y + 10)\degree + 50\degree = 180\degree \\ \\ = > 2y\degree + y\degree + 10\degree + 50\degree = 180\degree \\ \\ = > 3y\degree + 60\degree = 180\degree \\ \\ = > 3y\degree = 180\degree - 60\degree \\ \\ = > 3y\degree = 120\degree \\ \\ = > y = \frac{120\degree}{3\degree} \\ \\ = > y = 40\degree$

5 0

3 years ago

The x-intercepts of the gravy of f (x)= x (x+1)(x-5)(x-7) are

Serhud [2]

"Of the gravy" lol

To find the x-intercepts, you make f(x) = 0 and solve for x by setting each factor equal to 0.

0 = x(x + 1)(x - 5)(x - 7)

x = 0

x + 1 = 0
x = - 1

x - 5 = 0
x = 5

x - 7 = 0
x = 7

Your x-intercepts are x = - 1, 0, 5, 7

OR

There are x-intercepts at (- 1, 0), (0, 0), (5, 0), and (7, 0).

8 0

3 years ago

Convert 8100 mg to grams help me ?

sashaice [31]

It would be 8.1 grams

4 0

3 years ago

Read 2 more answers

Consider the initial value function y given by

Nuetrik [128]

Answer:

y(s) = $\frac{5s-53}{s^{2} - 10s + 26}$

we will compare the denominator to the form $(s-a)^{2} +\beta ^{2}$

$s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$

comparing coefficients of terms in s

$s^{2} :$ 1

s: -2a = -10

a = -2/-10

a = 1/5

constant: $a^{2}+\beta ^{2} = 26$

$(\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09$

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = $A(s-a)+B((s-a)^{2} +\beta ^{2} )$

we insert the values of a and β

$\\5s-53$ = $A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )$

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

the constants are

a = 0.2

β = 5.09

A = 5.4

B = -2

Step-by-step explanation:

since the denominator has a complex root we compare with the standard form $s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$
Expand and compare coefficients to obtain the values of a and β as shown above
substitute the values gotten into the function
Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0

3 years ago