Answer:
Perimeter of quadrilateral
will be ![104](https://tex.z-dn.net/?f=104)
Step-by-step explanation:
Given quadrilateral
is a reflection of quadrilateral
over the line
.
So, all the corresponding sides of both the quadrilateral should be equal.
Also, we can see from the diagram that ![A'D'=32,\ A'B'=22,\ BC=20,\ and\ CD=30](https://tex.z-dn.net/?f=A%27D%27%3D32%2C%5C%20A%27B%27%3D22%2C%5C%20BC%3D20%2C%5C%20and%5C%20CD%3D30)
As both image are reflection of same scale we can add corresponding sides.
So, the perimeter of
will be
![AB+BC+CD+DA](https://tex.z-dn.net/?f=AB%2BBC%2BCD%2BDA)
And we have ![AB=A'B'\ and\ AD=A'D'](https://tex.z-dn.net/?f=AB%3DA%27B%27%5C%20and%5C%20AD%3DA%27D%27)
Now, perimeter of
will be ![22+20+30+32](https://tex.z-dn.net/?f=22%2B20%2B30%2B32)
Perimeter of quadrilateral
is ![104](https://tex.z-dn.net/?f=104)
The area of a <span>isosceles triangle:
S=(bh)/2, where b is for base (=4) and h is for height (=x+3)
We get the equation:
10=(4*(x+3))/2
10=(4x+12)/2
4x+12=20
4x=8
x=2
</span>
Answer:
Step-by-step explanation:
yes congruent, by AAS
the angles are stating , w/ the little red lines that they are the same.. so we know two angles of the triangles are the same, and we also know that one side touching is the same. so yes.. AAS.
Thats easy its 7/6 hope this helps