Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
Answer:
∠ UVS = 39°
Step-by-step explanation:
The angle UVS is an inscribed angle and is half the measure of the intercepted arc, that is
∠ UVS = 0.5 × 78° = 39°
C is the answer bc its (5)^2-10(5)+25 so then it is 25-50+25 which = 0
Answer:
2hours and 17 minutes
Step-by-step explanation:
