<h2>
Option B is the correct answer.</h2>
Step-by-step explanation:
We need to find average value of 
in [2,4]
Area of in [2,4] is given by
![\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times \left [ e^{2x}\right ]^4_2\\\\\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times(e^8-e^4)=1463.18](https://tex.z-dn.net/?f=%5Cint_%7B2%7D%5E%7B4%7De%5E%7B2x%7Ddx%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5Cleft%20%5B%20e%5E%7B2x%7D%5Cright%20%5D%5E4_2%5C%5C%5C%5C%5Cint_%7B2%7D%5E%7B4%7De%5E%7B2x%7Ddx%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%28e%5E8-e%5E4%29%3D1463.18)
Area of in [2,4] = 1463.18
Difference = 4 - 2 = 2
Average value = Area of in [2,4] ÷ Difference
Average value = 1463.18 ÷ 2
Average value = 731.59
Option B is the correct answer.
Answer:
The true statements are (D) and (E). This is a square with sides equal to 5 units so that means that its perimeter is 4×(5 units) or 20 units and its area is (5 units)×(5 units) or 25 units^2.
Answer:
6
Step-by-step explanation:
22^4c-82. Is the equation I think you are looking for.
The Answer for your question is True......
