Answer:
3.90625×10^_03
Step-by-step explanation:
gshdieej
Answer:
HCF = 33.
Step-by-step explanation:
99 = 3*3*11
165 = 3*5*11
3 and 11 are common so the HCF = 3*11
= 33.
Solution :
a).
Given : Number of times, n = 25
Sigma, σ = 0.200 kg
Weight, μ = 13 kg
Therefore the hypothesis should be tested are :


b). When the value of 
Test statics :



= 45.5
P-value = 2 x P(Z > 45.5)
= 2 x 1 -P (Z < 45.5) = 0
Reject the null hypothesis if P value < α = 0.01 level of significance.
So reject the null hypothesis.
Therefore, we conclude that the true mean measured weight differs from 13 kg.
115 = 10X + 0.25(60)
115 = 10x +15 (this is the equation to use)
100=10x
x=10 hours