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Inga [223]
3 years ago
5

Jerry had 1 gallon of ice cream. He used 4/10 gallon to make chocolate milkshake and 0.30 gallon to make vanilla milkshake. How

much ice cream is left?
Mathematics
1 answer:
stiv31 [10]3 years ago
3 0
0.30 is the same as 3/10 so then you would add 3/10 and 4/10 which equals 7/10 which then gives you with 3/10 ice cream left
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Write the interval (5,100] as an inequality and using set notation
drek231 [11]

Answer: { x | 5 < x ≤ 100 }  OR  { x ∈ ℝ | 5 < x ≤ 100 }

Step-by-step explanation:

{ x | 5 < x ≤ 100 }

This means:

"The set of all x's, such that x is greater than 5 and less than or equal to 100"

Another acceptable way to write this is

{ x ∈ ℝ | 5 < x ≤ 100 }

"x ∈ ℝ" simply means x is an element of all real numbers

7 0
3 years ago
Which phrase best describes the relationship indicates by the scatter plotting?​
Inga [223]

Answer:B

Step-by-step explanation:

8 0
3 years ago
Find ( f - g)(x).<br><br> f (x) = -2x2 - 2x - 3 and g(x) = 3x2 - 4x - 4
Kruka [31]

Answer:

\large\boxed{(f-g)(x)=-5x^2+2x+1}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\\text{We have}\ f(x)=-2x^2-2x-3\ \text{and}\ g(x)=3x^2-4x-4.\\\\\text{Substitute:}\\\\(f-g)(x)=(-2x^2-2x-3)-(3x^2-4x-4)\\\\(f-g)(x)=-2x^2-2x-3-3x^2+4x+4\qquad\text{combine like terms}\\\\(f-g)(x)=(-2x^2-3x^2)+(-2x+4x)+(-3+4)\\\\(f-g)(x)=-5x^2+2x+1

3 0
3 years ago
-(4x - 5) + 16x ≥ -31<br> can you solve this inequality equation?
Elis [28]

Answer: x≥-3

Step-by-step explanation:

-(4x-5)+16x≥-31

-4x+5+16x≥-31

12x+5≥-31

   -5  -5

12x≥-36

12/12x≥-36/12

x≥-3

hope this helped :)

3 0
3 years ago
A cylinder has volume 78 cm3 . What is the volume of a cone with the same radius and height? A 26 cm3 B 39 cm3 C 156 cm3 D 234 c
otez555 [7]

Answer:

Option A - 26 \mathrm{cm}^{3}

Step-by-step explanation:

Given: The volume of a cylinder = 78 \mathrm{cm}^{3}

Let us substitute the volume of cylinder in the formula.

The formula for volume of a cone is V=\frac{\pi r^{2} h}{3}                    (1)

The formula for volume of a cylinder is V=\pi r^{2} h              (2)

Substituting V=78 in equation (2), we get,

\begin{array}{c}{V=\pi r^{2} h} \\{78=\pi r^{2} h}\end{array}

Given that the cone has the same radius and height of that of the cylinder, let us substitute 78=\pi r^{2} h in equation (1)

\begin{array}{l}{V=\frac{\pi r^{2} h}{3}} \\{V=\frac{78}{3}} \\{V=26}\end{array}

Thus, the volume of a cone with the same radius and height of a cylinder is 26 \mathrm{cm}^{3}.

3 0
3 years ago
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