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3 years ago

Need help with number 4

Mathematics

1 answer:

anastassius [24]3 years ago

8 0

Find the common denominators. for the miles 5 and 3 go into 15. so 2/5 times 3 is 6/15. and 2/3 times 5 is 10/15. for the hours 5 and 9 go into 45. 1/5 times 9 is 9/45. and 2/9 times 5 is 10/45. so Susan ran 6/15 of a mile in 9/45 of an hour. and Kim ran 10/15 of a mile in 10/45 of an hour.

so Kim ran 3 miles in an hour. Susan ran 2 miles in an hour.

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Given: PQ ⊥ QR , PR=20, SR=11, QS=5 Find: The value of PS.

dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0

3 years ago

I need help. ASAP! Divide. (3b^3 – 10b^2 + 4) ÷ (3b – 1)

viktelen [127]

Step-by-step explanation:

try surfing how to divide a function by the long division method

3 0

4 years ago

For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the ratios/percentages of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.