Answer:
At t=1, Rate of Change=-36.86
At t=10 hours, Rate of Change =-0.0088
Step-by-step explanation:
The function which describes the number of facts of a certain type which are remembered after t hours is given as:
To determine the Rate of Change at the given time, we first look for the derivative of f(t).
Applying quotient rule:
At t=1
=-36.86
At t=10 hours
=-0.0088
Vic and Dan are 2, 897m apart.
<h3>How to determine the distance</h3>
It is important to note that the distance between Vic and Dan is the base of CN
Let's say the distance to Dan is x
The distance to Vic is y
Using cosine ratio, we have
cos α = opposite / adjacent
α = 72°
opposite = 553. 3cm
Adjacent = x
cos 72° =
Cross multiply
×
=
m
The distance to Vic is y
Using the cosine ratio, we have
Cross multiply
m
To determine how far apart Vic and Dan, we use = x + y
= 1790. 61 + 1106. 6
= 2, 897. 21m
= 2, 897m
Thus, Vic and Dan are 2, 897m apart.
Learn more about bearing and distance here:
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Answer:
<u>5-number summary is:</u>
The numbers are added to the box plot.
See attached
