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WINSTONCH [101]
2 years ago
6

Simplify the expression -2x(x+3) A: -x -6 B: -x + 6 C: -2x + 6 D: -2x - 6​

Mathematics
1 answer:
Leni [432]2 years ago
3 0

Answer:

D

Step-by-step explanation:

-2x(x+3)

-2x-6

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<u>Given</u>:

The vertices of the quadrilateral WXYZ are W(2,4), X(4,2), Y(2,1) and Z(0,2)

The graph is rotated 90° about the origin.

We need to determine the coordinates of the quadrilateral W'X'Y'Z'

<u>Coordinates of the quadrilateral W'X'Y'Z':</u>

The rule to transform the coordinates 90° counter clockwise about the origin is given by

(x, y) \implies(-y, x)

Let us substitute the coordinates.

The coordinates of W' is given by

W(2,4)\implies W'(-4,2)

The coordinates of X' is given by

X(4,2) \implies X'(-2,4)

The coordinates of Y' is given by

Y(2,1) \implies Y'(-1,2)

The coordinates of Z' is given by

Z(0,2) \implies Z'(-2,0)

Therefore, the coordinates of the vertices W', X', Y' and Z' are (-4,2), (-2,4), (-1,2) and (-2,0) respectively.

5 0
3 years ago
If R is the total resistance for a parallel circuit with two resistors of resistances of r1 and r2 then 1/r=1/r1+1/r2 find the r
Allushta [10]
A little Algebra, and we're home free!

We are given R = 20 and r2 = 75. We need to find r1.

The formula is 1/R = 1/r1 + 1/r2. Plug-in:
1/20 = 1/r1 + 1/75
1/20 - 1/75 = 1/r1
0.0366 = 1/r1
r1 = 1/0.03666
r1 = 27.272

Our answer is r1 = 27 ohms.
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Oksanka [162]
The only safe conclusion is that point G lies on line FH or that point G lies somewhere between line FH. We cannot conclude that point G is the midpoint of line FH eventhough by virtue of definition of midpoint, the given equation is a proof equation. If G were to be midpoint, segment FG must be equal to segment GH in line FH. 
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