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8_murik_8 [283]
4 years ago
8

Can you solve the system of equation using substitution y=x+8 X+y=2

Mathematics
1 answer:
Vsevolod [243]4 years ago
8 0
X + y = 2
Substitute x + 8 into y
x + x + 8 = 2
2x + 8 =2
(Subtract 8 from both sides)
2x = -6
(Divide both sides by 2)
x = -3

Subsitute x = -3 into either equation to find y
x + y = 2
-3 + y = 2
(Add 3 to both sides)
y = 2 + 3
y = 5

Or y can be solved for using:
y = x + 8
y = -3 + 8
y = 5
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Which of the following statements describes the difference between the range and the interquartile range? A. The range is a numb
spayn [35]
Range is the difference between the max and min
IQR is the difference between Q3 and Q1.

It is LETTER C
7 0
3 years ago
The probabilities that stock A will rise in price is 0.59 and that stock B will rise in price is 0.41. Further, if stock B rises
Reil [10]

Answer:

1) 0.75

2) No, the 2 events are not mutually exclusive because P(A&B) ≠ 0

3)The 2 events are not independent because P(A | B) ≠ P(A).

Step-by-step explanation:

1) P(A) = 0.59 and P(B) = 0.41

Thus; to find the probability that at least one of the stocks will rise in price;

P(A or B) = P(A) + P(B) - P(A&B)

Now, we know that if B rises in price, the probability that A will also rise is 0.61 i.e P(A|B) = 0.61

Hence;P(A & B) = P(A|B) x P(B) =0.61 x 0. 41 = 0.25

So P(A or B) = 0.59 + 0.41 - 0.25 = 0.75

B) we want to find out if events A and B are mutually exclusive ;

P(A|B) = P(A&B)/P(B), For the events to be mutually exclusive, P(A&B) has to be zero. Since P(A&B) ≠ 0,the 2 events are not mutually exclusive.

C) Since P(A|B) = 0.61 and P(A) is 0.59. Thus, P(A | B) ≠ P(A).

So, therefore the 2 events are not independent.

8 0
3 years ago
Calcular cuántos números impares hay entre 20 y 50 y calcular su suma​
const2013 [10]

Answer:

<em>La suma de los impares entre 20 y 50 da 875</em>

Step-by-step explanation:

<u>Suma de Progresiones Artiméticas </u>

Una progresión aritmética es aquella en la cual, cada término se obtiene como el anterior mas una cantidad fija llamada diferencia común. El término general de una progresión aritmética es

a_n=a_1+(n-1)r

Donde a_1 es el primer término, n el número de términos y r la diferencia común o radio. La suma de los primeros n términos se calcula como:

\displaystyle S_n=n\frac{a_1+a_n}{2}

En nuestro ejercicio, se deben sumar los números impares entre 20 y 50, se forma la progresión

21, 23, 25, 27, ....49

Sabemos que a_1=21,\ a_n=49,\ r=2

Primero averiguamos cuántos términos son, despejando n del término general

\displaystyle n=\frac{a_n-a_1}{r}+1

\displaystyle n=\frac{49-21}{2}+1

\displaystyle n=25

La progresión tiene 25 términos

Ahora la suma es

\displaystyle S_{25}=25\frac{21+49}{2}

\displaystyle S_{25}=25\frac{70}{2}

S_{25}=875

La suma de los impares entre 20 y 50 da 875

6 0
4 years ago
In a study conducted to examine the quality of fish after 7 days in ice​ storage, ten raw fish of the same kind and approximatel
vesna_86 [32]

Question: The sample data and the scatter plot was not added to your question. See the attached file for the scatter plot.

Answer: Yes

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From scatter plot, it was discovered that there is a linear relationship between the two variables and both variables are quantitative.

Therefore, it appropriate to use the correlation coefficient to describe the strength of the relationship between​ "Time" and​ "Fish Quality"?

4 0
4 years ago
A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 4
bulgar [2K]

Answer:

\frac{dx}{dt}=4c-\frac{4}{15}x

Step-by-step explanation:

Data provided in the question:

Initial volume of water = 15 liters

Concentration of salt = 4 liters per minute

x be the amount of salt, in grams, in the fish tank after t minutes have elapsed

The unknown concentration of incoming brine c.

Now,

Salt concentration per minute = \frac{4}{15}

For x amount of salt =  \frac{4}{15}x

Therefore,

\frac{dx}{dt}=4c-\frac{4}{15}x

8 0
4 years ago
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