One kilometer is approximately 31/50 mile. what decimal represents this length?

Mathematics

1 answer:

ollegr [7]2 years ago

7 0

0.62

31X2=62
50X2=100
62 divided by 100 is 0.62

Hope that helps! :)

You might be interested in

Looking at the two, 7<img src="https://tex.z-dn.net/?f=a%5E%7B4%7D%20b%5E%7B2%7D%20c%5E%7B2%7D%20and14abc%5E%7B6%7D" id="TexForm

AlexFokin [52]

Answer:

$7abc^{2}$

Step-by-step explanation:

5 0

2 years ago

I Only Need #9 Not 10

Minchanka [31]

Answer:

Step-by-step explanation:

Remember the last question? to find circumference you have to multiply the diameter by 3.14? well same here except you divide the circumference by 3.14 to get the diameter. so divide 18.84 ÷ 3.14 = 6

~R3V0

$d= \frac{C}{\pi }$

$C = \pi d$ (pi times d)

5 0

2 years ago

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$