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3 years ago

An equiangular triangle can be scalene

Mathematics

1 answer:

uysha [10]3 years ago

4 0

Answer:

No, as a scalene triangle's sides are are different, while an equilateral's sides are all the same.

Hope that helps, :)

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A survey asked people of different ages whether they get their news by reading the paper. What is the probability that a person

Bingel [31]

C. 60%

The probability that a person surveyed is 40 or older and gets the news by reading the paper is 60%.

Step-by-step explanation:

In our case, we have to find the probability of a person getting their news by reading the paper. But we are given with a condition that the person must be 40 or older.

The survey is conducted among 80 people.

Number of people aged 40 or older = 40

No of people aged 40 or older and read paper = 24

Probability formula is the ratio of number of favorable outcomes to the total number of possible outcomes.

Probability of a person aged 40 or older reads a paper =

(No. of People aged 40 or older and read paper)/(No. of people aged 40 or older)

= 24/40

= 0.6

= 60%

Learn more about probability from brainly.com/question/10694003

#learnwithBrainly

8 0

3 years ago

Read 2 more answers

Line segment XY has endpoints X(5, 7) and Y(– 3, 3). Find the equation for the perpendicular bisector of line segment XY.

Veronika [31]

Answer:b

Step-by-step explanation:

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3 years ago

Which of the following are solutions to the cubic equation x^3+4x^2+4x=0

viktelen [127]

Answer:

337285

Step-by-step explanation:

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3 years ago

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3 years ago

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

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3 years ago