All categories

3 years ago

Can someone pls help, I know this is kind of a lot but I’ve been stuck on this for a while now.

Mathematics

1 answer:

Greeley [361]3 years ago

3 0

9514 1404 393

Answer:

(a, b, c) = (-0.425595, 11.7321, 2.16667)

f(x) = -0.425595x² +11.7321x +2.16667

f(1) ≈ 13.5

Step-by-step explanation:

A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.

Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...

a = -0.425595

b = 11.7321

c = 2.16667

f(x) = -0.425595x² +11.7321x +2.16667

and f(1) ≈ 13.5

_____

<em>Additional comment</em>

Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.

You might be interested in

45 percent of what is 27

Anarel [89]

Answer:

x = 60

Step-by-step explanation:

We have, 45% • x = 27

or,

45 /100 • x = 27

Multiplying both sides by 100 and dividing both sides by 45,

we have x = 27 • 100/ 45

x = 60

7 0

3 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

Which set of shapes could you use to form a net for a

Hoochie [10]

Answer:

Step-by-step explanation:

I did the assignment :>

5 0

3 years ago

Read 2 more answers

Create a numeric vector called age whose elements contain the ages of three people you know, where the names of each element cor

erik [133]

Answer:

age<-c(20,30,40)

names(age)<-c ("ELI", "ALI", "JON")age

## ELI ALI JON

## 20 30 40

Step-by-step explanation:

The above given vector named age consists of three elements. Each element consists of ages of three people, ELI, ALI and JON, such that 20 corresponds to ELI, 30 to ALI and 40 to JON.

8 0

3 years ago

Step 3: Displaying numerical data in dot plots, and describing and analyzing

mylen [45]

Answer:

Step-by-step explanation:

i added it all

4 0

3 years ago