Find the value of r 4(x-3)-r+2x=5(3x-7)-9x

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

r = 4(x-3)/5(3x-7) + 11x

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(x^2 + 5x + 2) – (5x^2 – x – 2) =

zlopas [31]

Answer:

${ \tt{( {x}^{2} + 5x + 2) - (5 {x}^{2} - x - 2) }} \\ = { \tt{(1 - 5) {x}^{2} + (5 + 1)x + (2 + 2)}} \\ = { \tt{ - 4 {x}^{2} + 6x + 4 }} \\ = { \tt{ - 2(2 {x}^{2} - 3x - 2) }}$

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3 years ago

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The total of a regular polygon's interior angles is 3420°.

DanielleElmas [232]

Step-by-step explanation:

(n-2)×180=3420

180n-360=3420

180n=3420+360

180n=3780

n=3780/180

n=21

that is, the number of sides is 21

to get the size of each exterior angle=

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2 years ago

Given sec(theta)= 5... find cot(90-theta)

Mumz [18]

$\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 } = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6} 
\\
$