Answer:
The given functions are


The sine function has a standard period of
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is
.
Now, the images of each function is the y-variable set values that defines each function.
So, the function
has an image defined by the set
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to
.
About the second function
, the image set is
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
Answer:
if she has 17 quarters, the money of it would be $4.25.
$5.05 - 4.25$ = $0.80
=> 8 dimes
=> she have 17 quarters and 8 dimes
Step-by-step explanation:
Answer:
It's the left graph, y = f(x)
Step-by-step explanation:
If you find the x-intercepts, you'd solve (2-3x)/x = 0. This means you'd really solve 2-3x=0, which gives you x=3/2.
So the graph must have an x-intercept at (1.5, 0). Only f(x) has that.
I believe that it is E since it is pretty obvious where the middle is you just do rise/run which gives you 2,-1
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