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Setler79 [48]
2 years ago
5

What is the surface area of the cylinder

Mathematics
1 answer:
sasho [114]2 years ago
6 0

Answer:

The formula to calculate the total surface area of a cylinder is expressed as, total surface area of cylinder = 2πr(r + h). This total surface area includes the area of the 2 bases (2πr2) and the curved surface area (2πrh). Here 'r' is the radius and 'h' is the height of the cylinder.

Step-by-step explanation:

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claudia bought a television at a 25% discount . the original price of the television was $349. there wasa 7% sales tax. how much
Scrat [10]
349 * .75 = $261.75
$261.75 * 1.07 = $280.07
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3 years ago
Y = 2/3 when x = 0.2
azamat
Please explain some more:)
4 0
3 years ago
help PLEASEE! Might post a lot of these sorry
ExtremeBDS [4]

Answer:

A = 189 sq units

Step-by-step explanation:

You can cut the shape up into pieces. See image. There are two rectangles and a triangle. Some sides are given:

rectangle: 16 × 8

sm rectangle: 3 × 4

Some sides you have to add to find (the height of the whole entire thing: 16+4+4)

Some lengths you have to subtract to find (height of the triangle: 24 - 10).

Area of a rectangle:

length × width OR

base × height

Area of a triangle:

1/2 • b • h

Add up all three areas. See image.

4 0
2 years ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
How do I solve this problem?
Anvisha [2.4K]

Answer:

y+11=-\frac{1}{4}(x-4)

Step-by-step explanation:

since the equation is perpendicular to y=4x-2, m=-1/4 (negative reciprocal). (x_1,y_1)=(4,-11), plug all the values into the equation y- y_1 = m(x-x_1) and we get y+11=-\frac{1}{4}(x-4)

8 0
3 years ago
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