Negative exponent will go down to become positive
7/g²g⁴=7/g⁶
Answer:
(4^-3)(x^-3) y^(18)
or
y^18/ (64 x^3)
Step-by-step explanation:
(4xy^-6)^-3
Distribute the exponent to all terms in the parentheses
(4^-3)(x^-3) (y^-6)^-3
a^ b^c = a^ (b*c)
(4^-3)(x^-3) y^(-6*-3)
(4^-3)(x^-3) y^(18)
If we do not want negative exponents
a ^ -b = 1/ a^b
y^18/( 4^3 x^3)
y^18/ (64 x^3)
Here is what I got for the first one. MAD=
1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|)
=1/5(|85-83|+|83-83|+|87-83|+|90-83|+|70-83|)
=1/5(2+0+4+7+13))
=5.2
And for the second one I got, MAD=
1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|)
=1/5(|75-76|+|74-76|+|68-76|+|83-76|+|80-76|)
=1/5(1+2+8+7+4))
=4.4
Answer: 7
Step-by-step explanation:
Factors of 7 are, 1, and 7. The factors of 21 are, 1, 3, 7, and 21, making 7 the gcf.
Answer:
Again, I already answered this in a thorough manner in a past post...look in your notifications.
Have a great day!
