Ask question

Ask question

All categories

goldfiish [28.3K]

3 years ago

9

Simplify. Write the expression using only positive exponents. 7g⁻²/g⁴

1 answer:

Arte-miy333 [17]3 years ago

6 0

Negative exponent will go down to become positive
7/g²g⁴=7/g⁶

You might be interested in

The volume formula of a right pyramid is V= 1/3 Bh. What does B represent?

tino4ka555 [31]

Answer:

B is the area of the base

Step-by-step explanation:

V= 1/3 Bh

V is the volume

B is the area of the base

h is the height of the pyramid

4 0

2 years ago

Read 2 more answers

What is the combined weight of the zoo’s African elephant and the rhino

mojhsa [17]

What is the separate weight

4 0

3 years ago

Read 2 more answers

Question 1 (1 point)

KatRina [158]

Answer:

97.2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The ratio for 3 turnovers : 12 assists as a fraction is?

slamgirl [31]

It is 3/12 and when you reduce it, it become 1/4

8 0

3 years ago

Read 2 more answers

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .

The number of fish tripled in the first year. This means that $P(1) = 3P(0) = 3(80) = 240$ .

Using the equation for P(1), that is, P(t) when $t = 1$ , we find the value of r.

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

$240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}$

$280*(2000 + 80(e^{r} - 1)) = 160000e^{r}$

$280*(2000 + 80e^{r} - 80) = 160000e^{r}$

$280*(1920 + 80e^{r}) = 160000e^{r}$

$537600 + 22400e^{r} = 160000e^{r}$

$137600e^{r} = 537600$

$e^{r} = \frac{537600}{137600}$

$e^{r} = 3.91$

Applying ln to both sides.

$\ln{e^{r}} = \ln{3.91}$

$r = 1.36$

This means that the expression for the size of the population after t years is:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

4 0

3 years ago