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Alexeev081 [22]
2 years ago
15

What is the value of x for which (8-x)^2=x^2

Mathematics
2 answers:
Yuri [45]2 years ago
6 0

Step-by-step explanation:

(8 - x)² = x²

=> 8 - x = x or 8 - x = -x (rejected)

=> x = 4.

I am Lyosha [343]2 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

{x}^{2}  =  {(8 - x)}^{2}

=  >  {x}^{2}  =  {x}^{2}  - 16x + 64

=  >  {x}^{2}  -  {x}^{2}  + 16x = 64

=  > 16x = 64

=  > x =  \frac{64}{16}  = 4

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