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xeze [42]
3 years ago
7

Your English teacher has decided to randomly assign poems for the class to read. The syllabus includes 2 poems by Shakespeare, 3

poems by Coleridge, 5 poems by Tennyson, and 4 poems by Lord Byron. What is the probability that you will be assigned a poem by Coleridge and then a poem by Lord Byron?
Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0
|\Omega|=14\cdot13=182\\
|A|=3\cdot4=12\\\\
P(A)=\dfrac{12}{182}=\dfrac{6}{91}
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The sum of a number and its reciprocal is <br> 61<br> 30<br> .<br> Find the numbers.
Maksim231197 [3]
Let's say the number is hmmm "a", its reciprocal would then be 1/a
thus \bf a+\cfrac{1}{a}=\cfrac{61}{30}

solve for "a"
7 0
3 years ago
There are seven roads that lead to the top of a hill. How many different ways are there to reach the top and then go back down?
rjkz [21]

Answer:

two I have no idea of the question

4 0
3 years ago
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The graph of the quadratic function y = ax^2 + bx + c is given.<br> Find a + b + c.
andrey2020 [161]

Answer:

\frac{145}{24}\approx 6***

Answers may vary depending on the person reading the graph.

It is hard to tell what they think crosses nicely.

For example, I decided that the graph crossed nicely at the following points:

(0,3)

(2,8)

(6,5)

Step-by-step explanation:

I see that the graph crosses at (0,3),(2,8), and (6,5).

The equation y=ax^2+bx+c tells us the y-intercept is c since when x=0 we have y=a(0)^2+b(0)+c=0+0+c=c.

The y-intercept for our graph is 3. Therefore, c=3.

So far we have the equation:

y=ax^2+bx+3.

Let's enter the other points creating a system of linear equations to solve:

8=a(2)^2+b(2)+3

5=a(6)^2+b(6)+3

Let's simplify:

8=4a+2b+3

5=36a+6b+3

Let's subtract 3 on both sides:

5=4a+2b

2=36a+6b

I choose to solve the system by elimination.

Let's multiply the top equation by -3:

-15=-12a-6b

2=36a+6b

Now adding the equations results in:

-13=24a

Divide both sides by 24:

\frac{-13}{24}=a

Now using one of the equations we can find b:

5=4a+2b with a=\frac{-13}{24}

5=4\frac{-13}{24}+2b

5=\frac{-13}{6}+2b

Add 13/6 on both sides:

5+\frac{13}{6}=2b

\frac{30+13}{6}=2b

\frac{43}{6}=2b

Divide both sides by 2:

\frac{43}{2(6)}=b

\frac{43}{12}=b

So we have the equation:

y=\frac{-13}{24}x^2+\frac{43}{12}+3

Let's evaluate a+b+c now:

\frac{-13}{24}+\frac{43}{12}+3

\frac{-13+86+72}{24}

\frac{73+72}{24}

\frac{145}{24}

4 0
3 years ago
Simplify. Assume that a is a positive integer and a&gt;2. (a-2)!/a!
Paul [167]

Answer:

C. 1 / (a(a - 1))

Step-by-step explanation:

View Image

Just know that:

n! = n(n-1)!

   = n(n-1)(n-2)!

   = n(n-1)(n-2)(n-3)!

   = ...

8 0
3 years ago
Read 2 more answers
Change to an improper fraction 4 2/3=
barxatty [35]
Solutions 

To solve the problem the first step is to m<span>ultiply the whole number by the fraction's denominator (4 x 3).Add the numerator (2) to the product. 

4 * 3 = 12 

12 + 2 = 14 

= 14/3 </span>
4 0
3 years ago
Read 2 more answers
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