Answer: The average number of cases per bid is <u>599</u>.
Step-by-step explanation:
Given: One week she put together bids for 680 cases, 507 cases, 830 cases, 391 cases, and 587 cases.
Total cases = 680 + 507 + 830 + 391+587
= 2995
Number of bids = 5
Now, average number of cases per bid = 

Hence, the average number of cases per bid is <u>599</u>.
Since the numbers are consecutive, they must be near each other in size, and therefore near one-third of 168. And since the lower number is -2 off the middle, and the upper number is +2 from the middle, the middle number must be exactly one-third of 168—otherwise the sum of the three could never be 168. Labelling the three consecutive numbers as x, y, and z:
x + y + z = 168
(y-2) + y + (y+2) = 168.
3y = 168
y = 56
therefore the smallest number (x) = 54.
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Related Questions (More Answers Below)
Answer:
And if we use the values obtained we got:
For this case this value means that the expected score is about 7.48
Step-by-step explanation:
For this case we assume the following probability distribution:
X 5 6 7 8 9 10
P(X) 0.05 0.15 0.33 0.28 0.12 0.07
First we need to find the expected value (first moment) and the second moment in order to find the variance and then the standard deviation.
In order to calculate the expected value we can use the following formula:
And if we use the values obtained we got:
For this case this value means that the expected score is about 7.48
In order to find the standard deviation we need to find first the second moment, given by :
And using the formula we got:
Then we can find the variance with the following formula:
And then the standard deviation would be given by:
Answer:
B, 11000
Step-by-step explanation:
assuming a 365 day year...

which I guess is close enough to 11000