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hichkok12 [17]
3 years ago
5

Plzzzzzzz i need this one done ssooooooon

Mathematics
2 answers:
aleksley [76]3 years ago
8 0

Answer:

2y

Step-by-step explanation:

2x3y + 18xy - 10x2y - 90y

6xy + 18xy - 20xy - 90y

All terms can be factored by y and 2.

Gwar [14]3 years ago
5 0

Answer:

Part A:

2y*3 x+2y*9x-2y*10-2y*45

sorry i am not sure for part A

Part B:

2y(2x-45y)

Step-by-step explanation:

Part A:

2y*3 x+2y*9x-2y*10-2y*45

Part B:

2x3y + 18xy − 10x2y − 90y

=2y(3x+9x-10x-45y)

= 2y(2x-45y)

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Find the value of the parallelogram
ruslelena [56]

Answer:

x=30

y=22.5

Step-by-step explanation:

each of the corners are 90

3x=90

divide each side by 3

x=30

4y=90

divide each side by 4

x=22.5

5 0
3 years ago
4. How many seconds will it take an echo to reach your ears if you yell toward a mountain
Flauer [41]
Sorry if it's low quality and blurry.

5 0
3 years ago
Please help could you explain or show work so I will remember how to do problems like this?
antiseptic1488 [7]

Answer:

x = -8

Step-by-step explanation:

4x - (x - 4) = - 20

Distribute the minus sign

4x - x +4 = -20

Combine like terms

3x+4 = -20

Subtract 4 from each side

3x+4-4 = -20-4

3x = -24

Divide by 3

3x/3 = -24/3

x = -8

3 0
3 years ago
Read 2 more answers
APPLICATIONS
n200080 [17]

Answer:

(a) (4,9), (8,14).; (b) 1.25 in/h; (c) d = 1.25h + 4 ; (d) 4 in; (e) 19 in

Step-by-step explanation:

(a) Information as coordinate pairs

4 h,  9 in ⟶ (4, 9)

8 h, 14 in ⟶ (8,14)

The coordinates of the two points are (4,9), (8,14).

(b) Slope of the line

\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\  & = & \dfrac{14 - 9}{8 - 4}\\\\& = & \dfrac{5}{4}\\\\& = & \mathbf{1.25}\end{array}

The slope of the line is 1.25 in/h

(c) Equation of the line

\begin{array}{rcl}d & = & mh + b\\9 & = & \dfrac{5}{4} \times 4 + b\\\\9& = & 5 + b\\b & = & \mathbf{4}\\\end{array}

The y intercept is at (0,4)  

d = 1.25h + 4

(d) Depth when snowfall began

\begin{array}{rcl}d &= &\text{0 h } \times \dfrac{\text{1.25 in}}{\text{1 h}} \text{+ 4 in}\\\\&= &\text{0 in+ 4 in}\\& = &  \textbf{4 in}\\\end{array}

The depth was 4 in when the snowfall began.

(e) Depth after 12 h

\begin{array}{rcl}d &= &\text{12 h } \times \dfrac{\text{1.25 in}}{\text{1h}} \text{+ 4 in}\\\\&= &\text{15 in+ 4 in}\\& = &  \textbf{19 in}\\\end{array}

The depth would be 19 in after 12 h.

The figure below is a graph of your function. It shows that the depth was 4 in at the start of the snowfall, that it increases by 5 in every 4 h, and predicts a depth of 19 in after 12 h.

8 0
3 years ago
Which is the equation of the line that passes through the points (4.3) and (2. 6)? Like how I do this because I had infinite ans
Cerrena [4.2K]

Answer: C

Step-by-step explanation: You have to graph the 2 points and plug in each answer until the slope passes through

4 0
3 years ago
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