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Natasha_Volkova [10]
3 years ago
7

Who would win in a fight, Hawk or Miguel? Cobra Kai!!

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0

Answer:

Honestly it could probably go either way

Step-by-step explanation:

lol that's a good question:D

shepuryov [24]3 years ago
7 0

Answer:

miguel

Step-by-step explanation:

no explanation needed

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Matrix M shows the one-way fares for four commuter train routes. Suppose the rail service lowers all fares by 15%. Which formula
Readme [11.4K]

Answer:

B) 0.85M

Step-by-step explanation:

The new fare schedule is the current fare schedule reduced by 15% of current fares:

... M - 0.15M = 0.85M

3 0
3 years ago
Solve for x <br> A 15 <br> B 16<br> C 2.4<br> D 12
Ne4ueva [31]

Answer: bd=8 dc=2 and ae=4 so value of ab=16

Step-by-step explanation:

7 0
2 years ago
One of ten different prizes was randomly put into each box of a cereal. If a family decided to buy this cereal until it obtained
Reptile [31]

Answer:

29.29

Step-by-step explanation:

The first trial among a distribution of independent trials with a constant success probability follows a geometric probability.

The expected value of a negative binomial is the reciprocal of its success probability <em>p.</em>

<em>E(X)=</em>1/<em>p</em>

At the first draw, we only selected one of the 10 prizes and so 1 draw gives a success

<em>E(X)=</em>1/<em>p</em>

<em>E(X1)</em>=1

After the first prize is drawn, we are interested in the first time (success), that we draw another prize that is different (<em>p</em>=9/10)

E(X2)=1/9÷10

E(X2)= 10/9

After the first prizes have being drawn, we now interested in the first time success that we draw a different prize from the first 2

E(X3)=1/8÷10

E(X3)=10/8

E(X3)=5/4

After the first three prizes have been drawn, we are now interested in the success of a first time draw for the 4th different prize

E(X4)=1/7÷10

E(X4)=10/7

Fifth different prize

E(X5)=1/6÷10

E(X5)=10/6

E(X5)=5/3

Sixth different prize

E(X6)=1/5÷10

E(X6)=10/5

E(X6)=2

Seventh different prize

E(X7)=1/4÷10

E(X7)=10/4

E(X7)=5/2

Eighth different prize

E(X8)=1/3÷10

E(X8)=10/3

Ninth different prize

E(X9)=1/2÷10

E(X9)=10/2

E(X9)=5

After the 9 different prizes have been drawn, we are interested in the first time we will draw the tenth different prize

E(X10)=1/1÷10

E(X10)=10

Add up all corresponding values;

<em>E(X)=</em>E(X1)+E(X2)+E(X3)+E(X4)+E(X5)+E(X6)+E(X7)+E(X8)+E(X9)+E(X10)

<em>E(X)=</em>1+10/9+5/4+10/7+5/3+2+5/2+10/3+5+10

<em>E(X)</em>= 29.29

Note: Those values in <em>E(X), </em>should be written the way it will in standard algebra ie they should be small.

4 0
3 years ago
En un hospital el 30 % de los pacientes que acuden de manera diaria presentan problemas cardíacos. Si un día acuden al hospital
juin [17]

Answer:

21 pacientes tienen problemas cardíacos de los 70 pacientes diagnosticados

Step-by-step explanation:

Paciente con problema cardíaco del total de pacientes diagnosticados = 30%

Total de pacientes que van al hospital en un día = 70

El total de pacientes con problemas cardíacos entre los 70 pacientes diagnosticados es

30% de 70 = 30/100 * 70 = 21

6 0
2 years ago
Help me please! !!!!!!!
Andrej [43]
The answer is c. 1/9. 

If x = -2, y = -1, z = 3

then,    (-2(-1) -(-1)^2) / 3(3)

(2 - 1)/3(3)

1/9

3 0
3 years ago
Read 2 more answers
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