1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jekas [21]
3 years ago
11

Three students share 2 packs of paper

Mathematics
1 answer:
klasskru [66]3 years ago
5 0

3 ÷ 2 = 1.5

So each student had a pack and a half.

Hope this helps. :)

You might be interested in
Please answer this question now in two minutes
Ira Lisetskai [31]

Answer:

the correct answer is (b).........

6 0
3 years ago
Read 2 more answers
How many different ways can you solve a quadratic equation ? List them.
Semmy [17]

There are three basic methods for solving quadratic equations: factoring, using the quadratic formula, and completing the square.

6 0
3 years ago
Find the 14 term of the following geometric sequence.<br> 10, 20, 40, 80,
vagabundo [1.1K]

Answer:

<u>81920</u>

Step-by-step explanation:

Finding the common ratio (r) :

  • 20/10
  • 2

Finding the 14th term :

  • a₁₄ = ar¹⁴⁻¹
  • a₁₄ = ar¹³
  • a₁₄ = (10)(2)¹³
  • a₁₄ = (10)(8192)
  • a₁₄ = <u>81920</u>
4 0
1 year ago
Read 2 more answers
Please give me the right answer and help, i’ll give brainliest❤️
nekit [7.7K]

Answer:

3:4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole
lozanna [386]

Answer:

A = 0.75 gram or 1 gram

Step-by-step explanation:

The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole number).

We can use the following formula for half-life of ^{14}C to find out how much is left from the original sample after 2,292 years:  

A = A_{0}e^{-0.000124t}

where:

<em>A</em> is the amount left of an original gram sample after <em>t</em> years, and  

A_{0} is the amount present at time <em>t</em> = 0.

The half-life of  ^{14}C  is the time <em>t</em> at which the amount present is one-half the amount at time <em>t </em>= 0.

If 1 gram of  ^{14}C is present in a sample,  

 Solve for A when t = 2,292:  

Substituting A_{0}  = 1 gram into the decay equation, and we have:  

A = A_{0}e^{-0.000124t}

A = A_{0}e^{-0.000124(2,292)}

A = 0.75 g or 1 g  

6 0
2 years ago
Other questions:
  • Can someone please help me on letter b. I am really confused.
    14·1 answer
  • Megan bikes west to get from her apartment to school after school she bikes 8 miles north to her friends house how far is megans
    13·1 answer
  • The slopes of LM and HN both equal 0. What can you conclude about the segments
    9·2 answers
  • Which of the following fractions would convert into a repeating decimal
    9·1 answer
  • What is the equation of the following line?​
    7·2 answers
  • What is the answer to 8y-5&lt;3
    10·1 answer
  • Caleb borrowed $1500 from his aunt. He plans to pay his aunt back in 9 months. If he
    5·1 answer
  • Round to the nearest hundreds place.
    13·2 answers
  • Please please help!! and if you could show work too that would be amazing!!!
    5·2 answers
  • What's my name<br><br> A. Lou Sahsshole<br> B. Dihcksl Ong<br> C. Gabe Itch<br> D. Moe Lester
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!