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anzhelika [568]
3 years ago
12

A survey of high school juniors found that 82% of students plan on attending college. If you pick three at random, what is the p

robability that at least two plan on attending college? Round to the nearest percent.
I answered the question incorrectly, thinking it was 36% but the correct answer was 91%. Can someone please tell me what I did wrong and what is the rule or process I need to take. The book never showed me any other way to solve this just this: P(x) = nCx P^x q^n-x, I just want to learn the right way to avoid mistakes again for the upcoming test.
Please and thank you
Mathematics
1 answer:
Andrew [12]3 years ago
6 0

Answer:

91%

You forgot to add 'all three'

Step-by-step explanation:

X ~ B(3, 0.82)

q = 1 - 0.82 = 0.18

Atleast 2 means:

X = 2, or 3

3C2(0.82)²(0.18) + 3C3(0.82)³(0.18)⁰

= 0.363096 + 0.551368

= 0.914464

= 91.4464%

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Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
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Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

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In the above lists, the common time is:

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<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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