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satela [25.4K]
3 years ago
14

I need help on this it’s about trig identities

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha

\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha  }{cos\alpha (1 + sin\alpha) }

\frac{1  + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha  }{cos\alpha + sin\alphacos\alpha  }

\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha  }

\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }

\frac{2}{cos\alpha }

2sec\alpha

2.-

   sec²x - tanxsecx

\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}

\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}

\frac{1 - sinx}{cos^{2}x }

\frac{1 - sinx}{1 - sin^{2}x }

\frac{1 - sinx}{(1 - sinx)(1 + sinx)}

\frac{1}{1 + sinx}

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