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Andreas93 [3]
3 years ago
7

ray ZP bisects ∠OZQ so that ∠OZP = 8x – 9 and ∠PZQ = 5x + 18. Find the value of x, and the measure of each angle. You must show

all work in order to receive credit!

Mathematics
1 answer:
Alborosie3 years ago
4 0
Since ZP is the bisector of ∠ OZQ, then we can say:

∠OZP = ∠PZQ

8x-9 = 5x+18 
8x-5x = 18 + 9
3x = 27  
x= 27/3 → x = 9

Now plugin the value of x in both angles:
a) 8x - 9 = 8(9) -9 and " 8x - 9 = 63°
b) 5x +18 = 5(9) + 18 and "5x+18" =63°


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5 0
3 years ago
Write the equation of a line parallel to y= 2x + 2 that passes through the point (-1,-7). Show your work.
oksian1 [2.3K]

Answer:

\large\boxed{y=2x-5}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

Parallel lines have the same slope. Therefore if given line is

y=2x+2

then the slope of our line is m=2.

We have the equation:

y=2x+b

The line passes through (-1, -7). Put the coordinsted pf the point to the equation:

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-5=b\to b=-5

Finally:

y=2x-5

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3 years ago
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6 0
3 years ago
Homework Help ASAP!
lutik1710 [3]

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5 0
3 years ago
VERY URGENT HAVE A TEST TO TAKE
Daniel [21]
The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.

The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius. 
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2² 
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x²+y²+4x-2y+1=0, which is answer b.

5 0
3 years ago
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