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Lady_Fox [76]
2 years ago
5

10 points

Mathematics
2 answers:
Rzqust [24]2 years ago
6 0

Answer:

FEB 16

Step-by-step explanation:

Diano4ka-milaya [45]2 years ago
3 0

Answer:

February 6th

Step-by-step explanation:

3 months before may 15 is February 15. Subtract 9 from 15 (1 week and 2 days) and you get 6 which leads you to your answer.

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Svetach [21]
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Help picture is shown!!!!
daser333 [38]
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Symmetry is when you split the shape, but they look the same. 
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6 out of 13 of your
Tasya [4]

Answer:

46.2%

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Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com
fredd [130]

f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}

f has critical points where the derivative is 0:

2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1

The second derivative is

f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}

and f''(-1)=\frac2e>0, which indicates a local minimum at x=-1 with a value of f(-1)=\frac1e.

At the endpoints of [-2, 2], we have f(-2)=1 and f(2)=e^8, so that f has an absolute minimum of \frac1e and an absolute maximum of e^8 on [-2, 2].

So we have

\dfrac1e\le f(x)\le e^8

\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx

\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}

5 0
3 years ago
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