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MrRissso [65]
3 years ago
5

Determina el termino que hace falta en cada trinomio, de modo que sea trinomio cuadrado perfecto. luego, factorizalo

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

1) El término faltante es b^{2} = 9. La forma factorizada del polinomio es (\pm 3 \cdot n^{3} \mp 3)^{2}, 2) El término faltante es \pm 10^{\frac{3}{2} }\cdot x^{\frac{5}{2}\cdot n }. La forma factorizada puede ser (\pm \sqrt{10} \cdot x^{\frac{5}{2}\cdot n} \pm 5)^{2} o (\pm \sqrt{10} \cdot x^{\frac{5}{2}\cdot n} \mp 5)^{2}, 3) El término faltante es \frac{1}{4} \cdot y ^{2\cdot n}. La forma factorizada es (\pm 3 \cdot x^{n} \pm \frac{1}{2}\cdot y^{n})^{2}.

Step-by-step explanation:

(This exercise is presented in Spanish and therefore explanation will be held in such language)

Un trinomio cuadrado perfecto es una expresión algebraica que responde a la siguiente identidad:

(a + b)^{2} = a^{2} + 2 \cdot a \cdot b + b^{2}

Este ejercicio pide completar cada trinomio cuadrado perfecto con el componente faltante:

1) 9\cdot n^{6} - 18 \cdot n^{3}...

El término central implica el producto

a = \pm 3\cdot n^{3}

2\cdot a \cdot b = - 18 \cdot n^{3}

2\cdot (\pm 3\cdot n^{3})\cdot b = -18\cdot n^{3}

\pm 6\cdot n^{3}\cdot b = -18 \cdot n^{3}

b = \mp \frac{18\cdot n^{3}}{6\cdot n^{3}}

b = \mp 3

El término faltante es b^{2} = 9. La forma factorizada del polinomio es (\pm 3 \cdot n^{3} \mp 3)^{2}.

2) 10\cdot x^{5\cdot n} + ... + 25

a^{2} = 10\cdot x^{5\cdot n}

a_{1} = +\sqrt{10}\cdot x^{\frac{5}{2}\cdot n } o a_{2} = -\sqrt{10}\cdot x^{\frac{5}{2}\cdot n }

b^{2} = 25

b_{1} = 5 o b_{2} = -5

Existen dos posibles soluciones (y cuatro combinaciones posibles):

Posibilidad 1:

2\cdot a_{1}\cdot b_{1} =  2\cdot (\sqrt{10}\cdot x^{\frac{5}{2}\cdot n }) \cdot  (5)

2\cdot a_{1}\cdot b_{1} = 10^{\frac{3}{2} }\cdot x^{\frac{5}{2}\cdot n }

Posibilidad 2:

2\cdot a_{2}\cdot b_{1} =  2\cdot (-\sqrt{10}\cdot x^{\frac{5}{2}\cdot n }) \cdot  (5)

2\cdot a_{1}\cdot b_{1} = -10^{\frac{3}{2} }\cdot x^{\frac{5}{2}\cdot n }

El término faltante es \pm 10^{\frac{3}{2} }\cdot x^{\frac{5}{2}\cdot n }. La forma factorizada puede ser (\pm \sqrt{10} \cdot x^{\frac{5}{2}\cdot n} \pm 5)^{2} o (\pm \sqrt{10} \cdot x^{\frac{5}{2}\cdot n} \mp 5)^{2}.

3) 9\cdot x^{2\cdot n} + 3\cdot x^{n}\cdot y^{n} +...

a = \pm 3\cdot x^{n}

2\cdot a \cdot b = 3\cdot x^{n}\cdot y^{n}

2\cdot (\pm 3 \cdot x^{n})\cdot b = 3 \cdot x^{n}\cdot y^{n}

\pm 6 \cdot x^{n}\cdot b = 3 \cdot x^{n}\cdot y^{n}

b = \pm \frac{3\cdot x^{n}\cdot y^{n}}{6\cdot x^{n}}

b = \pm \frac{1}{2}\cdot y^{n}

b^{2} = \frac{1}{4}\cdot y^{2\cdot n}

El término faltante es \frac{1}{4} \cdot y ^{2\cdot n}. La forma factorizada es (\pm 3 \cdot x^{n} \pm \frac{1}{2}\cdot y^{n})^{2}.

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  (a) 315°

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Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

<h3>(a)</h3>

The bearing of P from R is 180° different from the bearing of R from P it will be ...

  135° +180° = 315° . . . . bearing of P from R

__

<h3>(b)</h3>

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

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The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

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The fare for a taxi cab is $2.50 per passenger and $0.75 for each mile. A group of friends has $22.00
xeze [42]

For this case we have to:

x: Let the variable representing the number of people to travel in the group

y: Let the variable representing the number of miles traveled.

If friends only have $22 then we have the following inequality:

2.50x + 0.75y \leq22

Now, if there are three people in the group we have that x = 3.

2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33

The taxi can travel a maximum of 19.33 miles.

On the other hand, if the group wants to travel 10 miles then we have to y = 10.

2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8

Thus, they could travel a maximum of 5 people.

ANswer:

2.50x + 0.75y \leq22

Traveling 3 people, the taxi can travel a maximum of 19.33 miles

Traveling 10 miles, a maximum of 5 people can travel

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