Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
3x - 1 = 3x + 1
subtract 3x from both sides to get (-1 = 1). This is a false statement so it is: CONTRADICTION
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4x - 11 = 7
add 11 to both sides and then divide both sides by 4 to get . This statement is true only when x = so it is: CONDITIONAL
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2 - 8x = 2 - 8x
add 8x to both sides to get (2 = 2). This is a true statement so it is: IDENTITY
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x + 1 = -x + 4
add x to both sides, subtract 1 from both sides, and divide both sides by 2 to get . This statement is true only when x = so it is: CONDITIONAL
Answer: B, A, C, A
Answer:
X=5
Step-by-step explanation:
the sum has to equal 180 because its a linear pair,
10×5=50
26×5=130