Answer:
Approximately 68%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 1, standard deviation = 0.05.
Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.
0.95 = 1 - 0.05
1.05 = 1 + 0.05
So within 1 standard deviation of the mean, which by the Empirical Rule, is approximately 68% of values.
Answer:
$50.4
Step-by-step explanation:
12% of 45 is 5.4
5.4 + 45 = 50.4
Hope I helped! Have a great day :)
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Question 8 measurements. Angle H (acute) Angle M (obtuse) Angle K (acute)
Question 9 measurements. Angle P (right) Angle Q (obtuse) Angle R (acute) Angle S (obtuse) Angle T (right)
I think p=4
How I solved it:
5(-2)+2p+2(-1)=2p
-10+2p+-2=2p So cross out last
-2p -2p 2p:)
= -10+2p+-2
+10 +10 Cross out the 10
= 2p=8
= divide both sides by 2p
= 2p/2= 8/2
= cross out the 2.
= which leaves
= p=4 we get 4 because we divide 8 to 2:)
I don’t know if I’m right but yea...
