Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
You have the function

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Rewrite it in the following way:


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This <span>function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.
</span>
From the added graph of the function you can conclude that <span>the maximum number of moose that the forest can sustain at one time is 96.</span>
Answer: Correct choice is A.
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Answer:
p value= 2.228
Step-by-step explanation:
since average of two groups is being compared two-sample t-test will be performed.
degrees of freedom= 12-2=10
at α=.025 from t table
p value= 2.228