Question

A circle has diameter 9 cm

Answer 1

Answer:

See below  

Step-by-step explanation:

The diameter of the circle is 9 cm.

The largest dimension of a square is its diagonal.

d² = s² + s² = 2s²

If the side length equals 5 cm,

d² = 2 × 5² = 2 × 25 = 50

d = √50 ≈ 7.1 cm

Thus, the square has plenty of room to fit inside the circle.

Answer 2

Answer:

Step-by-step explanation:

diameter of the circle = 9 cm

side of square = 5 cm

As we know that the diagonal is maximum dimension in case of square, so if the length of diagonal is less than the diameter of the circle, then the square can fit into the circle else not.

First we need to find the length of the diagonal.

Let the length of diagonal is D.

By use of Pythagoras theorem

$D^{2}=side^{2}+side^{2}$

$D^{2}=2\times 5^{2}=50$

D = 7.07 cm

As the length of the diagonal is less than the diameter of the circle, so the square can fit into the circle.