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RUDIKE [14]
3 years ago
9

Solve the inequality. 2(4+2x)>5x+5 ​

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

x < 3

Step-by-step explanation:

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On a store counter are exactly two boxes containing only purple marbles and yellow marbles. Box A has 30 purple marbles and 20 y
klemol [59]

Answer: Our required probability would be 0.35.

Step-by-step explanation:

Since we have given that

Number of boxes = 2

Number of purple marbles in Box A = 30

Number of yellow marbles in Box A = 20

Number of purple marbles in Box B = 15

Number of yellow marbles in Box B = 35

So,  If Melanie randomly selects one of the boxes and then randomly selects one marble from that box.

Probability that the marble selected will be purple is given by

\dfrac{1}{2}\times \dfrac{20}{50}+\dfrac{1}{2}\times \dfrac{15}{50}\\\\=\dfrac{1}{2}(\dfrac{20+15}{50})\\\\=\dfrac{1}{2}\times \dfrac{35}{50}\\\\=\dfrac{35}{100}\\\\=0.35

Hence, our required probability would be 0.35.

4 0
3 years ago
Find the range f(x) =-2x-5 for the domain (-2,-1,1,2).
iVinArrow [24]

Answer:

{ - 9, - 7, - 3, - 1 }

Step-by-step explanation:

To obtain the range substitute the values of x from the domain into f(x)

f(- 2) = - 2(- 2) - 5 = 4 - 5 = - 1

f(- 1) = - 2(- 1) - 5 = 2 - 5 = - 3

f(1) = - 2(1) - 5 = - 2 - 5 = - 7

f(2) = - 2(2) - 5 = - 4 - 5 = - 9

range is { - 9, - 7, - 3, - 1 }

8 0
3 years ago
Help me to understand this:<br> V=lwh; l=14, w=8, h=3 (volume of a rectangular box)
Valentin [98]
V=lwh\ \ \ \ \ | l=14\ \ and\ \ w=8\ \ and\ \ h=3\\\\&#10;V=14*8*3=336\\\\&#10;Solution\ is\ V=336.
6 0
3 years ago
How many solutions does the following equation have? -3u=-3u-10
olga2289 [7]

Answer:

There are no solutions

Step-by-step explanation:

-3u=-3u-10

Add 3u to each side

-3u+3u=-3u+3u-10

0 = -10

This is never true so there are no solutions

3 0
3 years ago
What is the length of BC in the right triangle below?
sleet_krkn [62]

Answer:

F. 82

Step-by-step explanation:

To calculate the length of BC, Pythagoras theorem will be used.

It says, Hypotenuse^2 = Perpendicular^2 + Base^2

In our case, Perpendicular = AB = 18 and Base = AC = 80

therefore,

Hypotenuse^2 = 18^2 + 80^2 = 6724

Hypotenuse = BC = \sqrt{6724} = 82

6 0
3 years ago
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