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kotegsom [21]
3 years ago
6

A crane is lowering a concrete block from a height of 270 feet above the ground at a constant rate 2.5 feet per second. which fu

nction can be used to determine h, the height, in feet, above the ground of the concrete block after 5 seconds?
Mathematics
1 answer:
patriot [66]3 years ago
7 0
First, we multiply 2.5 feet per second by the amount of seconds we are given.

2.5 * 5 = 12.5 feet

Now, let's subtract that number from 270 to find the height after 5 seconds.

270 - 12.5 = 257.5 feet above the ground.

After 5 seconds, the block is 257.5 feet above the ground.
Hope that helped!
You might be interested in
Please answer as quickly as you can! ♥ Find two possible dimensions for a cylinder that has a volume of 64π cm³.
11Alexandr11 [23.1K]

Answer:

Possible dimensions are r=4\,\,cm\,,\,h=4\,\,cm and h=16\,\,cm\,,\,r=2\,\,cm

Step-by-step explanation:

Given:

Volume of a cylinder is 64\pi\,\,cm^3

To find: Dimensions of a cylinder

Solution:

Let r,h denote height of a cylinder.

Volume of a cylinder = \pi r^2h

Therefore,

64\pi=\pi r^2h\\64=r^2h\\4^2\,4=r^2h

One possible dimension can be r=4\,\,cm\,,\,h=4\,\,cm.

Also, 64=r^2h can be written as 16(2^2)=hr^2

So, another possible dimension can be h=16\,\,cm\,,\,r=2\,\,cm

3 0
3 years ago
Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of th
balandron [24]
The answer:

the main formula of the circle's equation is 
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius

if a point A(x', y') passes through the circle, so the equation of the circle can be written as 
(x'-a)²+ (y'-b)² = R², and that is  a main formula.


<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²

and we know that R= OA = OC= OB, 
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies

x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)²  so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
 -5= -2x -4y, when x = -3 /2   we obtain y = 2

the center is C(-3/2, 2)
7 0
3 years ago
Anybody know the answer???<br> f (-5) = ??
matrenka [14]

Answer:

7

Step-by-step explanation:

The function is f(x) so if x is replaced with a number, that's the value that x is in the equation. In this case, it'll be -5, so go to -5 on your graph. The y value is 7.

7 0
3 years ago
GEOMETRY - I NEED HELP!!!
Ainat [17]

Answer:

angle DLM= 21+50=71 degrees i think

Step-by-step explanation:

take the 2 from 2x and divide 42 by the 2 and you have your variable x solved

3 0
3 years ago
Amber built a large rectangular garden that is 9 meters long and had an area of 72 square meters, what is the perimeter of amber
drek231 [11]
So we know that the length of the rectangle is 9 meters.

In order to find area of a rectangle, you multiply the length by the width.

To find the width, you divide the area by the side you do have , which is 9 meters.

72 divided by 9 is 8.

So the width 8 meters, and now to find the perimeter you must add all sides of the rectangle.

9+9+8+8 = 34.

The perimeter of the rectangular garden is 34 meters.
7 0
3 years ago
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