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Nataly [62]
3 years ago
11

A college entrance exam company determined that a score of 23 on the mathematics portion of the exam suggests that a student is

ready for​ college-level mathematics. To achieve this​ goal, the company recommends that students take a core curriculum of math courses in high school. Suppose a random sample of 150 students who completed this core set of courses results in a mean math score of 23.6 on the college entrance exam with a standard deviation of 3.3. Do these results suggest that students who complete the core curriculum are ready for​ college-level mathematics? That​ is, are they scoring above 23 on the math portion of the​ exam? Complete parts​ a) through​ d) below.
Required:
a. State the appropriate null and alternative hypotheses.
b. Verify that the requirements to perform the test using the t-distribution are satisfied. Check all that apply.

A. The students were randomly sampled.
B. The sample size is larger than 30.
C. The students' test scores were independent of one another.
D. None of the requirements are satisfied.

c. Use the P-value approach at the α= 0.05 level of significance to test the hypotheses in part (a).
d. Write a conclusion based on the results.
Mathematics
1 answer:
levacccp [35]3 years ago
5 0

Answer:

oofy uwu

Step-by-step explanation:

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6(g-3h)

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6/6=1

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6(g-3h)

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101in

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3 0
3 years ago
Leah is having a brunch. She wants to serve her guests 2 gallons of juice that is 75% orange juice and 25% pineapple juice. She
Katen [24]

She wants to serve --------- >  2 gallons of juice that is 75% orange juice and 25% pineapple juice

then 

2*0.75------------------ > 1.5 gallons of orange juice

2*0.25------------------ > 0.5 gallons of pineapple juice


2 gallons------------ >1.5 gallons of orange juice+ 0.5 gallons of pineapple juice

if 1 gallons pineapple juice mixture--------------------- > 0.40 gallons pineapple juice

X------------------------------------------------------------------- > 0.50 gallons pineapple juice

X=50/40=1.25 gallons juice mixture

1.25 mixture gallons---- > 0.50 gallons pineapple juice+0.75 gallons orange juice

Therefore

(2-1.25)=0.75 gallons of orange juice

2 gallons------------ >0.75 gallons of orange juice+ <span>1.25 mixture gallons  </span>

0.75*(p)+1.25*(m)=2--------------- > (0.75/1.25)*(p)+(1.25/1.25)*m=2/1.25

0.60p+m=1.6

 The answer is 0.60p+m=1.6






5 0
3 years ago
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