The box plots show the heights, in centimeters, of the boys and the girls in gym class.

Solve 4/9x+7=1/2. Solve 1/8x−12=3/4.

Elenna [48]

$\# 1 \\\\ \frac{4}{9}x+7=\frac{1}{2} \\\\ \frac{4x}{9}=\frac{1}{2}-7^{(2} \\\\ \frac{4x}{9}=\frac{1-14}{2} \\\\ \frac{4x}{9}=-\frac{13}{2} \\\\ 4x=-\frac{9*13}{2} \\\\ x=-\frac{\frac{9*13}{2}}{4} \\\\ x=-\frac{117}{2}*\frac{1}{4} \\\\ \boxed{x=-\frac{117}{8}=-14\frac{5}{8}}$

$\#2 \\\\ \frac{1}{8}x-12=\frac{3}{4} \\\\ \frac{1}{8}x=\frac{3}{4}+12^{(4} \\\\ \frac{x}{8}=\frac{3+48}{4} \\\\ \frac{x}{8}=\frac{51}{4} \\\\ x=\frac{\not8*51}{\not4} \\\\ x=2*51 \\\\ \boxed{x=102}$

4 0

3 years ago

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Help me with this question, please!! I don't understand!!

Gwar [14]

Answer:

Presentation on theme: "Geometry Spheres CONFIDENTIAL."— Presentation transcript:

Step-by-step explanation:

Search this up and watch the video it may explain it to you better. I hope this helps!

6 0

3 years ago

A bank offers all savings accounts 5% interest compounded annually. If one account has a principal of $100 and another

arsen [322]

Answer:

From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days .

Step-by-step explanation:

Given as :

The principal for the first account = p = $100

The rate of interest = r = 5% compounded annually

The account gets double , so, Amount = A = $200

Let the time after which account gets double = t years

So, From Compound Interest method

Amount = Principal × $(1+\dfrac{\trxtrm rate}{100})^{\textrm time}$

As amount is double its principal

So, A = 2 × $100 = $200

Or, A = p × $(1+\dfrac{\trxtrm r}{100})^{\textrm t}$

Or, $200 = $100 × $(1+\dfrac{\trxtrm 5}{100})^{\textrm t}$

Or, $\dfrac{200}{100}$ = $(1.05)^{\textrm t}$

Or, 2 = $(1.05)^{\textrm t}$

Taking Log both side

$Log_{10}2$ = $Log_{10}(1.05)^{t}$

Or, 0.3010 = t $Log_{10}1.05$

Or, 0.3010 = t × 0.0211

∴ t = $\dfrac{0.3010}{0.0211}$

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

Again

Amount = Principal × $(1+\dfrac{\trxtrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\trxtrm r}{100})^{\textrm t}$

As amount is double its principal

So, A = 2 × $1000 = $2000

Or, $2000 = $1000 × $(1+\dfrac{\trxtrm 5}{100})^{\textrm t}$

Or, $\dfrac{2000}{1000}$ = $(1.05)^{\textrm t}$

Or, 2 = $(1.05)^{\textrm t}$

Taking Log both side

$Log_{10}2$ = $Log_{10}(1.05)^{t}$

Or, 0.3010 = t $Log_{10}1.05$

Or, 0.3010 = t × 0.0211

∴ t = $\dfrac{0.3010}{0.0211}$

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

Hence From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days . Answer

7 0

3 years ago

Given the lengths of two sides of a triangle, find the range for the length of the third side. Write an inequality.

djverab [1.8K]

Answer:

| a - b | < length of third side < a + b

Step-by-step explanation:

Visualize the two given sides of the triangle (let's call then a and b), joined at the vertex of the triangle, and forming an angle. We can join the other free end of these two segments, with another segment whose length would vary according to how tiny or large the angle is. We can spread the aperture of the angle they form as much as we can just below (not reaching this angle measure, because in such case, there will be no triangle of tangible area. In such case, the length of the joining segment will be limited by the addition of the two sides:

length of third side < a + b

In the case the aperture of the angle formed by the two given sides is diminished as much as possible to still form a measurable triangle, the angle has to be just larger than zero, and in such case, the segment joining the other to ends of a and b would be just larger than the absolute value of the difference between a and b:

length third side > | a - b|

These are the two extreme cases, and the length of the third side must be within these limits.

5 0

3 years ago

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Need help asap will mark brainliest

liubo4ka [24]

Answer:

1725 ft²

Step-by-step explanation:

$\frac{50+65}{2} *30$ = $\frac{115}{2} *30= 57.5*30 = 1725$