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RUDIKE [14]
2 years ago
5

What is the point of y-intercept of the graph shown below

Mathematics
2 answers:
charle [14.2K]2 years ago
5 0
The y-intercept is where the line crosses the y-axis

In this case the line crosses y-axis at (0,3)

Hope this helps :)
FrozenT [24]2 years ago
5 0
A - 3,0

The Y intercept is where the graph crosses through the vertical line or the Y. On the graph, if you count upward from each square, you’ll eventually hit 3 which is the y intercept.

Hope this helps!
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10
Jlenok [28]

Answer:

False

Step-by-step explanation:

3 0
2 years ago
Allison was looking at a map with the following scale indicator. 2 inches = 6 miles
xeze [42]

answer: 9

the answer is 9 because 6 ÷ 2 = 3, and if you multiply 3 with 3, you get 9. you multiply the number 3 because you need to find out the distance in miles, and since in inches it is 3, you need to multiply by 3 because that is the formula to get miles.

3 0
2 years ago
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Which of the following is a solution of the equation 9- 2x=-1?<br> 04<br> 05<br> 04<br> 0-5
8_murik_8 [283]

Answer:

the answer is 5

Step-by-step explanation:

9-2x=-1. you subtract the 9 from both sides, giving you -2x=-10. then you divide the -10 by -2 which gives you 5

8 0
3 years ago
Read 2 more answers
Find all solutions of each equation on the interval 0 ≤ x &lt; 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
2 years ago
Read 2 more answers
Jacob is cutting yarn for a craft project. He needs pieces of yarn that are 12 inches long, but he only has a ruler marked with
lara [203]

Answer:

30.48 centimeters

Step-by-step explanation:

We know that:

2.54 cm = 1 inch

To find how many centimeters are in 12 inches, you should:

2.54 x 12 = 30.48

So Jacob’s pieces of yarn should be 30.48 centimeters long.

Hope this helps!

5 0
3 years ago
Read 2 more answers
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