Answer:the weight after 225 days is
22885 kilograms
Step-by-step explanation:
The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.
The formula for the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
n is the number of terms of the sequence.
a is the first term
d is the common difference
We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225
Therefore
T225 = 2725 + (225 - 1)90
T225 = 2725 + 224×90 = 2725 + 20160
T225 = 22885
The answer is 4√6 4√x
Sorry if that looks confusing but it means small 4, big 6 and then small 4
Slope-intercept form: y = mx + b
m = the slope
b = y-intercept.
In this problem,
m = 3/5
b = ?
So far y = 3/5x + b
Let's plug the point (-3, -1) into our slope equation.
-1 = 3/5(-3) + b
Simplify the right side.
-1 = -9/5 + b
Add 9/5 to both sides.
4/5 = b
The equation is: y = 3/5x + 4/5
Answer choice A is correct.
Answer:
Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0
3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]
28x root5 = 10 root5 [ -10root5 turns to 10 root5 when transferred to RHS]
28x root 5/root5 =10
28x=10
x = 10/28
x = 0.35
Hope it helped u,
pls mark as the brainliest
^v^
Answer:
Am am not that big brain
Step-by-step explanation:
